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Q1. In a book fair 27.5% discount is offered on a book of Rs. 500, then find the discount.

Solution

Price space of space book space equals space Rs. space 500
Discount space offered space equals space 27.5 percent sign
Now comma space 27.5 percent sign space of space Rs. space 500 space equals space fraction numerator 27.5 over denominator 100 end fraction cross times 500 equals Rs. space 137.50
Thus comma space the space amount space of space discount space offered space on space book space is space Rs. space 137.50.
Q2. A farmer borrows Rs. 7000 from a co-operative society for 2 years at the rate of 12%. How much does he has to pay at the end of two years?

Solution

Principal space equals space Rs. space 7000
Rate space of space interest space equals space 12 percent sign
Period space equals space 2 space years
Interest space on space Rs. space 100 space for space 1 space year space equals space Rs. space 12
therefore space Interest space on space Rs. space 7000 space for space 2 space years space equals space Rs. space open parentheses fraction numerator 7000 space cross times space 2 space cross times space 12 over denominator 100 end fraction close parentheses equals space Rs. space 1680
Now comma space Amount space equals space Principal space plus space Interest space equals space Rs. space left parenthesis 7000 space plus space 1680 right parenthesis space equals space Rs. space 8680
Thus comma space the space farmer space has space to space pay space Rs. space 8680 space at space the space end space of space two space years.
Q3. The sales tax rate is 8%. If Rahul bought a new car and paid a sales tax of Rs 1,920, what was the cost of the car before the tax?

Solution

Let  us say the car costs Rs y.   That would mean that y multiplied by 8% is Rs 1920.  y(8%) = 1920 8% could also be expressed as 0.08 Thus, y(0.08) = 1920 y =Rs 24000 The car costs Rs 24000 without tax.
Q4. Convert the following ratios into percentage: 1) 3 : 5 2) 1 : 4

Solution

1 right parenthesis space 3 space colon space 5 space equals space 3 over 5 cross times 100 space equals space 60 percent sign
2 right parenthesis space 1 space colon space 4 space equals space 1 fourth cross times 100 space equals space 25 percent sign
Q5. 15 boys earn Rs. 600 in 4 days, how much will 20 boys earn in 7 days?

Solution

In space 4 space days comma space 15 space boys space earn space Rs. space 600.
rightwards double arrow space In space one space day space 15 space boys space earn space equals space Rs. space 600 over 4 equals Rs. space 150
rightwards double arrow space One space boy space earns space in space one space day space equals space Rs. space 150 over 15 equals Rs. space 10
rightwards double arrow space One space boy space earns space in space 7 space days space equals space Rs. space left parenthesis 10 space cross times space 7 right parenthesis space equals space space Rs. space 70
rightwards double arrow space 20 space boys space earn space in space 7 space days space equals space Rs. space left parenthesis 20 space cross times space 70 right parenthesis space equals space Rs. space 1400 space space
Q6. Find the marked price of an article which is bought for Rs. 13489 after a discount of 18%.

Solution

Selling space price space equals space Rs. space 13489
Discount space equals space 18 percent sign
Now comma space Selling space price space equals space Marked space price space cross times open parentheses fraction numerator 100 space minus space Discount over denominator 100 end fraction close parentheses
rightwards double arrow space 13489 space equals space Marked space price space cross times space open parentheses fraction numerator 100 space minus space 18 over denominator 100 end fraction close parentheses
rightwards double arrow space 13489 space equals space Marked space price space cross times space open parentheses 82 over 100 close parentheses
rightwards double arrow space Marked space price space equals space 13489 space cross times space 100 over 82 space equals space Rs. space 16450
Q7. The catalogue price of a colour T.V. is Rs. 18,000. The shopkeeper gives a discount of 8% on the marked price. He gives a further off-season discount of 5% on the balance. But sales tax at 10% is charged on the remaining amount. Find  (i) the sales tax amount a customer has to pay. (ii) the final price he has to pay for the colour T.V.

Solution

begin mathsize 12px style Catalogue space price equals List space price equals Rs. space 18 comma 000
Discount equals 8 percent sign space of space Rs. space 18 comma 000 equals 8 over 100 cross times 18 comma 000 equals Rs. space 1 comma 440
Price space after space discount equals List space price minus Discount equals Rs. space left parenthesis 18 comma 000 minus 1 comma 440 right parenthesis equals Rs. space 16 comma 560
Off minus season space discount equals 5 percent sign space of space Rs. space 16 comma 560 equals 5 over 100 cross times 16 comma 560 equals Rs. space 828
Sale space price equals Rs. space left parenthesis 16 comma 560 minus 828 right parenthesis equals Rs. space 15 comma 732
left parenthesis straight i right parenthesis space The space sales space tax space amount space straight a space customer space has space to space pay equals 10 percent sign space of space Rs. space 15 comma 732 equals 10 over 100 cross times 15732 equals Rs. space 1573.20
left parenthesis ii right parenthesis space The space final space price comma the space cutsomer space has space to space pay space for space the space colour space straight T. straight V. space equals Sale space price plus Sales space tax
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space Rs. space left parenthesis 15 comma 732 plus 1573.20 right parenthesis
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space Rs. space 17305.20 end style
Q8. Find the selling price when marked price is Rs. 300 and discount is 5%.

Solution

Marked space price space equals space Rs. space 300
Discount space equals space 5 percent sign space on space straight M. straight P.
space space space space space space space space space space space space space space space space space equals space 5 over 100 space cross times space 300
space space space space space space space space space space space space space space space space space equals space Rs. space 15
therefore space Selling space price space equals space Marked space price space minus space Discount space equals space Rs. space left parenthesis 300 space minus space 15 right parenthesis space equals space Rs. space 285
Q9. A shopkeeper announces a discount of 15% on his goods. If the marked price of an article, in his shop, is Rs. 1,850, how much a customer has to pay for it, if the rate of sales tax is 9%?

Solution

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Q10. Find the C.I. on Rs 54,000 at 12% p.a for 2 years.

Solution

  C.I. on Rs 54,000 at 12% p.a for 2 years is Rs 13,737.60
Q11. Neeta has Rs. 500. Out of this, she bought a jacket for Rs. 400. Find the amount she spent in percentage.

Solution

Total space amount space with space Neeta space equals space Rs. space 500
Amount space spent space on space jacket space equals space Rs. space 400
400 space out space of space 500 space can space be space expressed space in space fraction space form space as space 400 over 500.
therefore space Percentage space equals space 400 over 500 cross times 100 space equals space 80 percent sign
Thus comma space Neets space spent space 80 percent sign space of space her space money.
Q12. Ashok invested a sum of Rs 67850 for 4 years at the rate of 7.8% p.a. Calculate the amount standing to his credit at the end of second year.

Solution

P =Rs 67850 T= 4 years Rate = 7.8% p.a.   Amount at the end of 1 st year = 67850 + 5292.30 = Rs.73142.30   Amount at the end of 2 nd year = 73142.30 + 5705.10 = Rs.78847.40 The amount standing to his credit at the end of second year = Rs.78847.40    
Q13. On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. What is the cost price of one ball?

Solution

Cost space price space of space 17 space balls space minus space Selling space price space of space 17 space balls space equals space Cost space price space of space 5 space balls space space space space left parenthesis given right parenthesis
rightwards double arrow space Cost space price space of space 12 space balls space equals space Selling space price space of space 17 space balls space equals space Rs. space 720
rightwards double arrow Cost space price space of space one space ball space equals space 720 over 12 equals space Rs. space 60
Therefore comma space the space cost space price space of space one space ball space is space Rs. space 60.
Q14. Which one is more profitable? Selling a phone whose cost price is Rs. 9865 at a profit of 20%. OR Selling a tablet at Rs. 12,750 with a profit of Rs. 1275.

Solution

Cost space price space of space phone space equals space Rs. space 9865
Profit space percent sign space space equals space 20 percent sign space
therefore space Selling space price space equals space fraction numerator open parentheses 100 plus Profit percent sign close parentheses over denominator 100 end fraction cross times straight C. straight P.
space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator open parentheses 100 plus 20 close parentheses over denominator 100 end fraction cross times 9865
space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 120 over 100 cross times 9865
space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space Rs. space 11 comma 838 space
therefore space Profit space equals space Rs. space left parenthesis 11 comma 838 space – space 9865 right parenthesis space equals space Rs. space 1973
Now comma space profit space made space on space selling space straight a space tablet space equals space Rs. space 1275
Since comma space profit space made space on space selling space the space phone space is space more space than space that space of space straight a space tablet comma
selling space the space phone space is space more space profitable. space
Q15. A, B and C together can do a work in 10 days. A alone can do the work in 20 days and B alone can do it in 30 days. How long will C take to do the work alone?

Solution

Total space time space taken space by space straight A comma space straight B space and space straight C space to space complete space the space work space equals space 10 space days
therefore space left parenthesis straight A space plus space straight B space plus space straight C right parenthesis apostrophe straight s space one space day apostrophe straight s space work space equals space 1 over 10
Time space taken space by space straight A space alone space to space do space the space work space equals space 20 space days
therefore space straight A apostrophe straight s space one space day space work space equals space 1 over 20
Time space taken space by space straight B space alone space to space do space the space work space equals space 30 space days
therefore space straight B apostrophe straight s space one space day space work space equals space 1 over 30
Now comma space straight C apostrophe straight s space one space day space work
equals space left parenthesis straight A space plus space straight B space plus space straight C right parenthesis apostrophe straight s space one space day space work space minus space left parenthesis straight A space plus space straight B right parenthesis apostrophe straight s space one space day space work
equals 1 over 10 space minus space open parentheses 1 over 20 plus 1 over 30 close parentheses
equals 1 over 10 space minus space 1 over 20 minus 1 over 30
equals fraction numerator 6 space minus 3 minus 2 over denominator 60 end fraction
equals 1 over 60
Thus comma space straight C space alone space can space do space the space work space in space 60 space days.
Q16. Find: 1)  16% of Rs. 75 2)  19% of 200 cm

Solution

1 right parenthesis space space 16 percent sign space of space Rs. space 75 equals space 16 over 100 cross times 75 space equals space Rs. space 12
2 right parenthesis space space 19 percent sign space of space 200 space cm space equals space 19 over 100 cross times 200 space equals space 38 space cm space
Q17. Sujit saves Rs. 1200 per month after spending 85% of his salary. What is his monthly salary?

Solution

Let space the space salary space of space Sujit space be space Rs. space 100.
Then comma space amount space spent space by space Sujit space equals space 85 over 100 cross times 100 equals Rs. space 85
Sujit apostrophe straight s space savings space equals space Rs. space left parenthesis 100 space minus space 85 right parenthesis space equals space Rs. space 15
Now comma space if space savings space is space Rs. space 15 comma space his space income space equals space Rs. space 100
therefore space If space savings space is space Rs. space 1200 comma space his space income space equals space 100 over 15 cross times 1200 space equals space Rs. space 8000
Thus comma space monthly space salary space of space Sujit space is space Rs. space 8000.
Q18. Mr. Lal buys a transistor, costing Rs. 625, for Rs. 650 including sales tax. Calculate the rate of sales tax charged.  

Solution

Marked price of transistor = Rs. 625 Total price (including sales tax ) = Rs. 650 Sales tax paid = Rs. 650 - Rs. 625 = Rs. 25 begin mathsize 12px style therefore space Rate space of space sales space tax equals 25 over 625 cross times 100 percent sign equals 4 percent sign end style Rate of sales tax is 4%.  
Q19. Calculate the compound interest on principal Rs.30000 and rate of interest 5 % for three years.

Solution

text S. I  =  end text fraction numerator text P  ×  R  ×  T end text over denominator 100 end fraction P = Rs. 30000, R = 5%, T = 3 Yrs Interest space for space 1 space st space year space equals space fraction numerator 30000 space cross times space 5 cross times space 1 over denominator 100 space end fraction equals 1500 Amount after 1 st year= P + S.I Amount = 30000 + 1500 = Rs.31500   straight C. straight I space for space 2 space nd space year space equals space fraction numerator 31500 space cross times space 5 cross times space 1 over denominator 100 space end fraction equals 1575 Amount after 2nd year = 31500 + 1575 = Rs. 33075 straight C. straight I space for space 3 space rd space year space equals space fraction numerator 33075 space cross times space 5 cross times space 1 over denominator 100 space end fraction equals 1653.75 C.I for 3 years = 1500 + 1575 + 1653.75 = Rs.4728.75
Q20. Two taps take 8 hours and 12 hours respectively to fill a tank. Find the time taken to fill the tank if they are open at the same time.

Solution

Time space taken space by space first space pipe space equals space 8 space hours
therefore space In space 1 space hour space it space fills space open parentheses 1 over 8 close parentheses to the power of th space part space of space the space tank
Time space taken space by space second space pipe space equals space 12 space hours
therefore space In space 1 space hour space it space fills space open parentheses 1 over 12 close parentheses to the power of th space part space of space the space tank
therefore space Total space work space done space in space 1 space hour space equals space 1 over 8 plus 1 over 12 equals fraction numerator 3 plus 2 over denominator 24 end fraction equals 5 over 24
therefore space Time space taken space equals space 24 over 5 space hours space equals space 4 4 over 5 space hours
Q21. Find the ratio of the first quantity to the second. 70 paise, Re 1

Solution

First space quantity space equals space 70 space paise
Second space quantity space equals space Re space 1 space equals space 100 space paise
therefore space Ratio space of space the space first space quantity space to space the space second
space space space space space equals space 70 over 100
space space space space space equals space fraction numerator 70 divided by 10 over denominator 100 divided by 10 end fraction
space space space space space equals space 7 over 10
space space space space space equals space 7 space colon space 10
Thus comma space required space ratio space is space 7 space colon space 10.
Q22. A shopkeeper offers 10% discount on the marked price of his articles and still makes profit of 20%. What is the actual cost of the article marked Rs. 500 for him?

Solution

Marked space price space equals space Rs. space 500
Discount space equals space 10 percent sign
therefore space straight S. straight P. space equals space Rs. space 500 space minus space 10 percent sign space of space Rs. space 500 space
space space space space space space space space space space space space space space equals space Rs. space 500 space minus space 10 over 100 cross times Rs. space 500 space
space space space space space space space space space space space space space space equals space Rs. space 500 space minus space Rs. space 50 space
space space space space space space space space space space space space space space equals space Rs. space 450
Now comma space profit space equals space 20 percent sign
therefore space straight C. straight P. space equals space Rs. space open parentheses fraction numerator 450 space cross times space 100 over denominator 120 end fraction close parentheses equals space Rs. space 375 space
Q23. Mita's weight decreased from 50 kg to 40 kg. Find the percentage decrease.

Solution

Decrease space in space Mita apostrophe straight s space weight space equals space left parenthesis 50 space minus space 40 right parenthesis space equals space 10 space kg
therefore space Percent space decrease space equals space 10 over 50 cross times 100 space equals 20 percent sign space
Q24. When a plot is sold for Rs. 18,700, the owner loses 15%. At what price the plot should be sold in order to gain 15%?

Solution

Selling space price space of space plot space equals space Rs. space 18 comma 700
Loss percent sign space equals space 15 percent sign space
Now comma space straight S. straight P. space equals space fraction numerator open parentheses 100 minus Loss percent sign close parentheses over denominator 100 end fraction cross times straight C. straight P.
rightwards double arrow straight C. straight P. space equals space fraction numerator 100 over denominator open parentheses 100 minus Loss percent sign close parentheses end fraction cross times straight S. straight P.
space space space space space space space space space space space space space space equals fraction numerator 100 over denominator left parenthesis 100 minus 15 right parenthesis end fraction cross times 18700
space space space space space space space space space space space space space space equals 100 over 85 cross times 18700
space space space space space space space space space space space space space space equals space Rs. space 22 comma 000
Now comma space we space want space straight a space gain space of space 15 percent sign.
therefore space straight S. straight P. space equals space fraction numerator open parentheses 100 plus Gain percent sign close parentheses over denominator 100 end fraction cross times straight C. straight P.
space space space space space space space space space space space space space space equals fraction numerator open parentheses 100 plus 15 close parentheses over denominator 100 end fraction cross times 22000
space space space space space space space space space space space space space space equals 115 over 100 cross times 22000
space space space space space space space space space space space space space space equals Rs. space 25 comma 300
Thus comma space the space plot space should space be space sold space at space Rs. space 25 comma 300 space to space earn space 15 percent sign space profit. space
Q25. A ruler costs Rs. 9 while a scissor costs Rs. 21. Find the ratio of the cost of the scissor to that of the ruler.

Solution

Cost space of space straight a space ruler space equals space Rs. space 9
Cost space of space straight a space scissor space equals space Rs. space 21
therefore space Ratio space of space the space cost space of space the space scissor space to space that space of space straight a space ruler
space space space space space space equals 21 over 9
space space space space space space equals fraction numerator 21 divided by 3 over denominator 9 divided by 3 end fraction
space space space space space space equals 7 over 3
space space space space space space equals 7 space colon space 3
Thus comma space required space ratio space is space 7 space colon space 3.
Q26. Find the compound interest and the amount to be paid for Rs. 15,000 for 3 years at 10% when the interest is compounded  half yearly.

Solution

Principal space equals Rs. space 15 comma 000
straight n equals 3 space years
straight R equals 10 percent sign
therefore space Amount space when space interest space compounded space half space yearly comma
space space space space space space straight A equals straight P open parentheses 1 plus straight R over 200 close parentheses to the power of 2 straight n end exponent
space space space space space space space space space equals 15000 space open parentheses 1 plus 10 over 200 close parentheses to the power of 2 cross times 3 end exponent
space space space space space space space space space equals 15000 open parentheses 210 over 200 close parentheses to the power of 6
space space space space space space space space space equals 15000 cross times 21 over 20 cross times 21 over 20 cross times 21 over 20 cross times 21 over 20 cross times 21 over 20 cross times 21 over 20 space
space space space space space space space space space equals Rs. space 20101.4
Now comma space straight C. straight I. space equals space straight A space minus space straight P space equals space Rs. space left parenthesis 20101.4 space minus 15000 right parenthesis space equals space Rs. space 5101.4
Q27. A loan of Rs. 20000 is taken from the bank at the compound interest of 8% p.a. Find the difference between the compound interest and the simple interest at the same rate on the loan amount for the period over 3 years.

Solution

P = Rs.20000, R = 8%, T = 3 Years. straight S. straight I space equals space fraction numerator straight P space cross times space straight R space cross times space straight T over denominator 100 end fraction= fraction numerator 20000 space cross times space 8 space cross times space 3 over denominator 100 end fraction
Rs.4800 Computation of Compound Interest: Interest space for space 1 space st space year space equals space fraction numerator 20000 space cross times 8 space cross times space 1 over denominator 100 end fraction equals 1600 Amount at the end of 1 st year = 20000 + 1600 = Rs.21600 straight C. straight I space for space 2 space nd space year space equals space fraction numerator 21600 space cross times 8 space cross times space 1 over denominator 100 end fraction equals 1728 Amount at the end of 2 nd year = 21600 + 1728 = Rs.23328   straight C. straight I space for space 3 space rd space year space equals space fraction numerator 23328 space cross times 8 space cross times space 1 over denominator 100 end fraction equals 1866.24 C.I for the 3 years = 1600 + 1728 + 1866.24 = Rs 5194.24       Difference between S.I and C.I = 5194.24 - 4800 =  Rs.394.24
Q28. Smita got an increase of 10% in her salary. Later, it was decreased by 10%. Is there any change in the income? If yes, what is the total change in per cent in her income?

Solution

Let space the space income space be space Rs. space 100.
After space 10 percent sign space increase comma space salary space equals space Rs. space left parenthesis 100 space plus space 10 right parenthesis space equals space Rs. space 110
After space 10 percent sign space decrease comma space salary space equals space Rs. space 90 over 100 cross times 110 space equals space Rs. space 99
therefore space Percent space decrease space in space salary
space space space space space equals space fraction numerator Change space in space income over denominator Original space income end fraction space cross times space 100 space
space space space space space equals space 1 over 100 space cross times space 100 space
space space space space space equals space 1 percent sign
Thus comma space the space salary space has space decreased space by space 1 percent sign.
Q29. A purchases an article for Rs. 3,100 and sells it to B for Rs. 4,250. B in turn sells it to C for Rs. 5,000. If VAT is 10%, find the VAT levied on A and B.

Solution

Q30. One tap can fill a cistern in 2 hours and the waste pipe can empty the full cistern in 5 hours. In what time will the empty cistern be full, if the tap and the waste pipe are kept open together?

Solution

Time taken by One tap to fill the cistern = 2 hours Part of the cistern filled by one tap in 1 hour = 1 half Time taken by waste pipe to empty the cistern = 5 hours Part of the cistern emptied by waste pipe 1 hour = 1 fifth Thus, part of the cistern filled in 1 hour = 1 half minus 1 fifth equals fraction numerator 5 minus 2 over denominator 10 end fraction equals 3 over 10 Hence, cistern will be filled completely in 10 over 3= 3.3 hours (approx.)
Q31. What percent of numbers from 1 to 50 have squares that end in the digit 1?

Solution

Numbers space from space 1 space to space 50 space having space their space squares space ending space in space digit space 1 space are
1 comma space 9 comma space 11 comma space 19 comma space 21 comma space 29 comma space 31 comma space 39 comma space 41 comma space 49 comma
straight i. straight e. space there space are space 10 space numbers
therefore space Required space percentage space equals space 10 over 50 space cross times space 100 space equals space 20 percent sign
Q32. Find the ratio of the second quantity to the first: 75 cm, 1.5 m

Solution

Second space quantity space equals space 1.5 space straight m space equals space left parenthesis 1.5 space cross times space 100 right parenthesis space cm space equals space 150 space cm
First space quantity space equals space 75 space cm
therefore space Ratio space of space the space second space quantity space to space the space first
space space space space space equals space 150 over 75
space space space space space equals space fraction numerator 150 divided by 75 over denominator 75 divided by 75 end fraction
space space space space space equals space 2 over 1
space space space space space equals space 2 space colon space 1
Thus comma space required space ratio space is space 2 space colon space 1.
Q33. A chair is sold for Rs. 1550 at a loss of Rs. 450. Find the loss percent. 

Solution

Selling space price space of space chair space equals space Rs. space 1550
Loss space equals space Rs. space 450
therefore space Cost space price space of space the space chair space equals space Rs. space left parenthesis 1550 space plus space 450 right parenthesis space equals space Rs. space 2000
Loss space percent sign space equals space fraction numerator Loss over denominator straight C. straight P. end fraction cross times 100
space space space space space space space space space space space space space space space equals space 450 over 2000 cross times 100
space space space space space space space space space space space space space space space equals space 45 over 2
space space space space space space space space space space space space space space space equals space 22 1 half
space space space space space space space space space space space space space space space equals space 22.5
Hence comma space loss space incurred space is space 22.5 percent sign. space space
Q34. Before adding VAT at 21%, an item's cost is Rs 200. Calculate the total cost after VAT is added.

Solution

  Total cost with VAT = cost without VAT + 21% of cost without VAT = Rs {200 + (0.21 x 200)}   = Rs (200 + 42)   = Rs 242   After VAT is added, the total cost is Rs 242.
Q35. The weight of a 10 year old girl was 32 kg. But it was misread as 36 kg. Find the error percentage.

Solution

Actual weight of the girl = 32 kg. Error = 36 kg - 32 kg = 4 kg.   Hence,  «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnalign=¨left¨ rowspacing=¨0¨»«mtr»«mtd»«mi»Percentage«/mi»«mo»§nbsp;«/mo»«mi»Error«/mi»«mo»§nbsp;«/mo»«mo»=«/mo»«mo»§nbsp;«/mo»«/mtd»«/mtr»«mtr»«mtd/»«/mtr»«mtr»«mtd»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mfenced»«mrow»«mfrac»«mrow»«mi»Error«/mi»«mo»§nbsp;«/mo»«/mrow»«mrow»«mi»Actual«/mi»«mo»§nbsp;«/mo»«mi»Weight«/mi»«mo»§nbsp;«/mo»«/mrow»«/mfrac»«mo»§nbsp;«/mo»«mi»x«/mi»«mo»§nbsp;«/mo»«mn»100«/mn»«/mrow»«/mfenced»«mo»%«/mo»«/mtd»«/mtr»«mtr»«mtd/»«/mtr»«mtr»«mtd»«mo»=«/mo»«mo»§nbsp;«/mo»«mfenced»«mrow»«mfrac»«mn»4«/mn»«mn»32«/mn»«/mfrac»«mo»§nbsp;«/mo»«mi»x«/mi»«mo»§nbsp;«/mo»«mn»100«/mn»«/mrow»«/mfenced»«mo»§nbsp;«/mo»«mo»%«/mo»«/mtd»«/mtr»«mtr»«mtd»«mfenced close=¨§nbsp;¨ open=¨§nbsp;¨»«mrow»«mo»=«/mo»«mo»§nbsp;«/mo»«mfrac»«mn»100«/mn»«mn»8«/mn»«/mfrac»«/mrow»«/mfenced»«/mtd»«/mtr»«mtr»«mtd»«mo»=«/mo»«mo»§nbsp;«/mo»«mfrac»«mn»25«/mn»«mn»2«/mn»«/mfrac»«mo»§nbsp;«/mo»«/mtd»«/mtr»«mtr»«mtd»«mo»=«/mo»«mo»§nbsp;«/mo»«mo»§nbsp;«/mo»«mn»12«/mn»«mfrac»«mn»1«/mn»«mn»2«/mn»«/mfrac»«mo»%«/mo»«/mtd»«/mtr»«/mtable»«/math» Hence, the percentage error is «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mn»12«/mn»«mfrac»«mn»1«/mn»«mn»2«/mn»«/mfrac»«mo»§nbsp;«/mo»«mo»%«/mo»«/math» .
Q36. Find the C.I. on Rs.24,000 at 15% p.a for 2 years.

Solution

begin mathsize 11px style U sin g space A space equals space P open parentheses 1 space plus space R over 100 close parentheses to the power of n
A space equals space 24000 open parentheses 1 space plus space 15 over 100 close parentheses squared
equals space 24000 open parentheses 23 over 20 close parentheses squared end style A = 60 × 23 × 23 A = Rs.31740 C I = Rs.(31740 - 24000) = Rs.7740 C.I. on Rs.24,000 at 15% p.a for 2 years is Rs.7740.
Q37. If the simple interest on a sum at 4% per annum for two years is Rs 80, then how much is the compound interest on the same sum for the same period? 

Solution

P = Rs.1000 C.I on Rs. 1000 for first year = Syntax error from line 1 column 319 to line 1 column 326. Unexpected '</mo>'.  Amount = S.I + P = 1000 + 40 = 1040  Therefore, Principal for second year = Rs. 1040 C.I on Rs. 1000 for second  year = Syntax error from line 1 column 340 to line 1 column 347. Unexpected '</mo>'. Therefore compound interest for two years = 40 + 41.60 = Rs.81.60
Q38. Which one of the following is cheaper to buy? The ceiling fan sold at a loss of 15% whose cost price is Rs. 900. OR A table fan whose selling price is Rs. 785.

Solution

Cost space price space of space ceiling space fan space equals space Rs. space 900
Loss space percent sign space equals space 15 percent sign space
therefore space Selling space price space equals space open parentheses fraction numerator 100 minus loss percent sign over denominator 100 end fraction close parentheses cross times straight C. straight P.
space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space open parentheses fraction numerator 100 space minus space 15 over denominator 100 end fraction close parentheses cross times 900
space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 85 over 100 cross times 900
space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals Rs. space 765
Now comma space selling space price space of space table space fan space equals space Rs. space 785
Since space selling space price space of space ceiling space fan space is space less space than space that space of space table space fan comma
buying space straight a space ceiling space fan space is space cheaper. space space
Q39. The marked price of a floor spread is Rs. 650. If the shopkeeper gives a discount of 6%, what is its selling price?

Solution

Marked space price space equals space Rs. space 650
Discount space equals space 6 percent sign
Discount space on space the space marked space price
equals space Marked space price space cross times space Discount
equals space 650 space cross times space 6 over 100
equals Rs. space 39
Selling space price space equals space Marked space price space minus space Discount space equals space Rs. space left parenthesis 650 space minus space 39 right parenthesis space equals space Rs. space 611
Thus comma space the space selling space price space of space the space floor space spread space is space Rs. space 611.
Q40. Reduce the following ratio in simplest form: 2 kg 250 g : 1 kg 500 g

Solution

begin mathsize 14px style 2 space kg space 250 space straight g space equals space 2250 space straight g space space space space left parenthesis 1 space kg space equals space 1000 space straight g right parenthesis
1 space kg space 500 space straight g space equals space 1500 space straight g
therefore space Required space ratio equals 2250 over 1500 equals 3 over 2 equals 3 space colon space 2 end style


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